|
QUIZ 3 |
||||||||||||||||||
|
Exercises and Problems from Conceptual Physics: Note that answers to odd numbered problems are listed in the paperback supplement "Practicing Physics." |
||||||||||||||||||
|
Ch 6 |
exercises |
impulse |
2 |
4 |
8 |
momentum |
13 |
16 |
42 |
|
|
|
|
|
|
|||
|
|
problems |
impulse |
2 |
3 |
momentum |
6 |
7 |
9 |
|
|
|
|
|
|
||||
|
Ch 7 |
review questions |
10 |
exercises |
15 (see fig 7.12) |
20 |
21 |
28 |
30 |
48 |
50 |
54 |
|
|
|
|
|
||
|
|
problems |
2 |
4 |
|
|
|
|
|
|
|
|
|
|
|||||
|
|
||||||||||||||||||
|
exercises |
||||||||||||||||||
|
2. large time means small force...see fig 6.5.. |
||||||||||||||||||
| 4. fig. 6.5 | ||||||||||||||||||
| 8. | Impulse | = I = | change in momentum | = mv = Ft so that v = Ft/m. Now, the force F that kills a person and the mass m are fixed numbers. The difference is the time t. | ||||||||||||||||||
| 13. momentum = mv. Does m change??? | ||||||||||||||||||
| 16. see fig. 6.11 | ||||||||||||||||||
|
|
||||||||||||||||||
| 2. mv = Ft. | ||||||||||||||||||
|
6 |
||||||||||||||||||
|
|
||||||||||||||||||
|
exercises |
||||||||||||||||||
21. The direction of motion shown. It is NOT horizontal. The weight, of
magnitude mg, points down. The two components of this downward vector are
shown. One is along the motion. This force component does work on
the object moving in that direction. The other is perpendicular to the
component along motion. If the motion was horizontal, there would be NO
component of gravitation force along the motion, and no work  |
||||||||||||||||||
|
30.Same speed. On the the bottom track, as it goes down the middle dip, the second ball gains more kinetic energy than the first ball, but loses the same amount of kinetic energy again after the leaving the dip. |
||||||||||||||||||
|
54 .Momentum is conserved. See. Fig 6.15. Kinetic energy is not conserved since the objects come to rest... |
||||||||||||||||||
|
Problems |
||||||||||||||||||
|
|
||||||||||||||||||
|
|
||||||||||||||||||
|
|
||||||||||||||||||