Quiz 15  AU11 Due at START of class Monday November 28th. Thanks for your cooperation.

SECTION 5.4

1. Factor.    x² - 169. 

2. Factor.    x²  - 144.

3. Factor.    x²   -  24x  +  144.

4. Factor.    x²  +  24x  +  144.

SECTION 5.5

5.  Factor COMPLETELY.    x³  -  24x²  +  144x. Hint. First factor out x. Then continue factoring until COMPLETE.

6.  Factor COMPLETELY.    x³  -  6x²  +  9x. Hint. See previous problem.

7.  Factor by grouping.    x³  +  3x²  +  4x  + 12.  HINT. See class notes. Worked this out on whiteboard last week. Also see #38, #44 along with example 7 in section 5.1.

SECTION 5.6

For the following solve using the principle of zero products:  A·B = 0 means A = 0 or B = 0.

8. SOLVE USING THE PRINCIPLE OF ZERO PRODUCTS:
(x + 1)(x + 5) = 0

9. SOLVE USING THE PRINCIPLE OF ZERO PRODUCTS:
(x - 1)(x - 5) = 0. Note differences and similarities with the previous problem.

10.  FIRST FACTOR THE LEFT HAND SIDE OF THE EQUATION.  THEN SOLVE USING THE PRINCIPLE OF ZERO PRODUCTS:
x²  +  6x  +  5 = 0. Note differences and similarities with the two previous problems.

11.  FIRST FACTOR THE LEFT HAND SIDE OF THE EQUATION.  THEN SOLVE USING THE PRINCIPLE OF ZERO PRODUCTS:
x²  -   5x  +  4 = 0.

12.  FIRST FACTOR THE LEFT HAND SIDE OF THE EQUATION.  THEN SOLVE USING THE PRINCIPLE OF ZERO PRODUCTS:
x²  +  8x  = 0. Hints:  There are two solutions and one of them is x = 0. Find the other solution for x.  See example 5. 

13.    EXTRA CREDIT:   SECTION 5.3 PROBLEM

FACTOR:  7x²  +  15x + 2. 

HINT ~ SEE PAGE 319 AND DISCUSSION OF THE GROUPING METHOD. SEE THE 6 STEPS GIVEN AND READ EXAMPLES 6  AND 7  FOR  PRACTICE. 

14.    EXTRA CREDIT:   SECTION 5.3 PROBLEM

FACTOR:  9x²  +  18x  +  5 .

HINT ~  SEE PAGE 319 AND DISCUSSION OF THE GROUPING METHOD. SEE THE 6 STEPS GIVEN AND READ EXAMPLES 6  AND 7  FOR  PRACTICE.