|
Test 1, on quizzes 1 to 5, is on Wednesday, July 5.
|
|
answers: b b c b b a b b a b b a b
|
|
3.2
|
|
1. Write equations for this problem. The sum of two numbers is 7. If
one number is subtracted from twice the other, the result is -1
|
a
x + y = -1
2x - y = 7
|
b
x + y = 7
2x - y = -1
|
c
x + y = 7
2x + y = -1
|
|
d nota
|
|
2. In the previous problem, the solution for x is
|
|
a 1
|
|
b 2
|
|
c 3
|
|
d nota
|
3. The cost and revenue functions for producing and selling x units
of a CD are given by
C(x) = 15,000 + 12x and R(x) = 32x, respectively. What is x in
order to break even?
|
| a 7,500
|
|
b 75 |
|
c 750 |
|
d nota |
|
3.3 |
4.
Is ( 2,-1,3) a solution to this system?
x + y + z = 4
x - 2y - z = 1
2x - y - z = -1 |
| a yes |
|
b no |
|
c nota |
|
3.3
|
| 5.
For the system:
x - y + z = 4 (A)
x + 2y - z = -1 (B)
x + y - 3z = -2 (C)
If you want to eliminate x, then you should |
| a Add
(B) and (A) and subtract (C) from (A) |
|
b Subtract
(B) from (A) and subtract (C) from (A) |
|
c Subtract
(B) from (A) and add (C) and (A) |
|
d nota |
| 4.1
|
| 6. Solve: 10x -6 > 14
|
| a x
> 2 |
| b x
< 2 |
| c x
< -2 |
| d nota |
7. Solve: -33(2 - b) < 12(2b + 2)
|
|
a b >
10 |
|
b b <
10 |
|
c b <
-10 |
|
d nota |
| 4.2 |
| 8. Solve: 0 < ½ x - 4
< 6 |
|
a 8 > x
> 20 |
|
b 8 < x
< 20 |
|
c no
solution |
|
d nota |
| 4.3 |
| 9. Solve |x - 2| = -9 |
a no
solution
|
b 11
or -7
|
c -11 or 7
|
d nota
|
| 10. Solve |3x + 2| = 16 |
|
a 6,
-14/3 |
|
b -6, 14/3 |
|
c -6, -14/3 |
|
d nota |
| 11. Solve |3x + 2| < 16 |
|
a 6 < x
< - 14/3 |
|
b -6
< x < 14/3 |
|
c -18 <
x < 14 |
|
d nota |
| 12. |3x + 2| > 16 |
|
a x < -6
or x > 14/3 |
|
b x < 6
or x > -14/3 |
|
c x <
-6 or x > -14/3 |
|
d nota |
| 13. EC Solve |3x + 2| + 6 =
22 |
|
a 6,
-14/3 |
|
b -6, 14/3 |
|
c -6,
-14/3 |
|
d nota |
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|