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| answers: b c b a c c a b a a a d |
| 2.4
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For the first two problems, write the point slope form for the
lines satisfying the conditions below.
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1. slope = 2/3, passing through (-6, 2)
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a. y - 6 = (2/3)(x + 2)
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b. y - 2 = (2/3)(x + 6)
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c. y - 2 = (2/3)(x - 6)
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d. y + 2 = (2/3)(x - 6)
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e. nota
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2. Passing through (4,7) and (10,
8)
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b. y -10 = (1/6)(x - 8) |
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c. y - 8 = ( 1/6)(x - 10) |
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d. y -10 = 6(x - 8) |
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e nota |
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3. Find the slope m and y-intercept (0,b) of the line given by problem
1. |
| a m = 2/3,
y-intercept = (0,4) |
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b m = 2/3, y-intercept = (0,6) |
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c m = 2/3,
y-intercept = (0,-6) |
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d. nota |
| 4. Find the slope and y-intercept of the
line given by problem 2. |
| a m = 1/6,
y-intercept = (0,19/3) |
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b m = 6, y-intercept = (0,19/3) |
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c m = 1/6, y-intercept = (0,10) |
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d nota |
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5. Write an equation for the line in point-slope form: Passing through
(2,7) and perpendicular to the line whose equation is y = (1/6)x +
5. (See page 136 for a discussion of perpendicular
lines. We covered a similar problem for parallel lines in class. ) |
| a y - 2 = -6(x - 7) |
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b y - 7 = 6(x - 2) |
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c y - 7 = -6(x - 2) |
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d nota |
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6. Yo, write the previous problem in slope -intercept form. |
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a y = -6x + 45 |
| b y = 6x - 5 |
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c y = -6x + 19 |
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d nota |
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3.1
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7. Is (2,-1) a solution to
3x + 4y = 2
2x + 5y = -1 ?
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| a yes |
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b no
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c nota
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8. Are the two lines of the previous problem
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a parallel ?
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b not parallel ?
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c nota
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9. Solve by substitution :
x - 3y = 3
3x + 5y = -19.
The solution for y is a value between
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a -3 and 0
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b 0 and 3
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c 3 and 6
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d nota
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10. The solution for x in the previous problem is a value between
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a - 4 and 0
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b 0 and 4
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c 4 and 8
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d nota
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11.
Solve by addition :
x - 3y = 3
3x + 5y = -5.
The solution for y is a value between
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a -3 and 0
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b 0 and 3
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c 3 and 6
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d nota
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12. The solution for x in the previous problem is
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a 1
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b 2
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c -6
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d 0
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e nota
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