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| answers: c b c b a b b b (answers to
writtens are below) |
| 2.4
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For the first two problems, write the point slope form for the
lines satisfying the conditions below.
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1. slope = 2/3, passing through (6, 2)
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a. y - 6 = (2/3)(x + 2)
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b. y - 2 = (2/3)(x + 6)
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c. y - 2 = (2/3)(x - 6)
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d. y + 2 = (2/3)(x - 6)
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e. nota
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2. Passing through (7,4) and (8, 10)
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b. y -10 = 6(x - 8) |
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c. y - 8 = ( 1/6)(x - 10) |
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d. y + 10 = 6(x - 8) |
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e nota |
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3. Find the slope m and y-intercept (0,b) of the line given by problem
1. |
| a m = 2/3,
y-intercept = (0,-4) |
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b m = 2/3, y-intercept = (0,6) |
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c m = 2/3,
y-intercept = (0,-2) |
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d. nota |
| 4. Find the slope and y-intercept of the
line given by problem 2. |
| a m = 1/6,
y-intercept = (0,-48) |
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b m = 6, y-intercept = (0,-38) |
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c m = 1/6, y-intercept = (0,-38) |
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d nota |
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5. Write an equation for the line in point-slope form: Passing through
(7,2) and perpendicular to the line whose equation is y = 6x +
5. |
| a y - 2 = -(1/6)(x - 7) |
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b y - 7 = 6(x - 2) |
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c y - 7 = -6(x - 2) |
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d nota |
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6. Yo, write the previous problem in slope -intercept form. |
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a y = -6x + 7/6 |
| b y = -(1/6)x + 19/6 |
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c y = -(1/6)x + 7/6 |
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d nota |
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3.1
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7. Is (2,1) a solution to
3x + 4y = 2
2x + 5y = -1 ?
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| a yes |
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b no
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c nota
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8. In the previous problem, the two lines |
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a intersect at (2,1) |
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b intersect at (2,-1) |
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c nota
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written problems |
Solve by substitution :
I
x - 3y = 3
II
6x + 10y = -38.
9. Find the solution for y = -2
10. Find the solution for x = -3
Hint: Write equation I as
x = 3y + 3 and substitute into II.
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Solve by addition :
I
x - 3y = 6
II
2x + 5y = -10
11. Find the solution for y = -2
12. Find the solution for x = 0
Hint: Multiply equation I by -2 and add I and II to eliminate x, yo.
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