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CH. 26: 4, 16, 19,
28, 31, 43, 44, 46, 48, 49 |
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QUIZ 7, CHAPTER 26 PROBLEMS |
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Simulation: Click here for the motion of an electron in a uniform electric field. |
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4. Internal resistance is often given the symbol r, a small case letter to suggest it is small. See fig. 26-1 and related discussion. Terminal voltage is defined to be Vab = ε - i*r (eqn. 26-1) , where ε is the voltage across the battery when no current flows. i.e. when i = 0. In the case at hand, you are given ε = 12.0 (V). You are also given i and Vab. Find r. |
| 16. See class notes. Convert the 820 ohm and 680 ohm resistors into a parallel equivalent given by Rp = (680)*(820)/(680 + 820) ohms. Then evaluate the sum Rp + 960 ohm for the effective series connection. |
| 19. See class notes. Convert the two
identical resistors in series into one resistor of value 2R.
Note 2R is parallel with R; the parallel
equivalent of these is (2/3)*R. Now find the equivalent resistor of the above-mentioned resistors in the part of the circuit above the R between point A and C. This equivalent resistor is R + (2/3)*R = 1.67*R; this resistor is parallel with the R between point A and C and is given by (1.67*R*R)/(1.67R + R). Add this last expression to R in order to compute the total equivalent resistor between points A and C. |
| 28. Find the total current by using
Kirchoff's second rule or loop rule, page 684. You will
discover the current i flows clockwise around the circuit. Then find 18 (V) - i*r2 and 12(V) + i*r1. In the last expression , we add because the change across the battery and internal resistor have the same sign. |
| 31. This is a good one. At junction a, I1 + I2 - I3 = 0. For the rest , see example 26-9. |
| 43. See example 26-14, dealing with turn signals. Both turn signals and windshield wipers involve repetitive motions based upon alternate charging and discharging. A typical turn signal flashes perhaps twice per second and a typical windshield wiper wipes once per second up or down. |
| 44. (a) RC = 24x10-6 seconds; find C given R. (b) Use equation 26-6a for the charge on the positive plate of the capacitor. Q = C*E(1 - e-t/RC), where E = 24.0 (V). The voltage across the resistor has magnitude I*R. To get I , differentiate the expression for Q: I = dQ/dt. You will get a decaying exponential of the form Io*e-t/RC. Note Io = E/R. Thus, I*R = E*e-t/RC , where E = 24.0 (V). Find the time it takes I*R to decrease from 24.0 (V) to 16.0 (V) |
| more discussions to come! |