QUIZ 1(ANSWERS)Problems below correspond to
online assignment 
CH. 1  DISCUSSION QUESTIONS 1, 4, 7 
CH 1  EXERCISES/PROBLEMS: 10; 11; 15; 13; 56; 26; 27. 
CH. 4  DISCUSSION QUESTIONS 1, 2, 5, 6 
CH. 4  EXERCISES/PROBLEMS: 1, 3, 4, 6 

HINTS: 

CH. 1  DISC QUESTIONS: 1, 4, 7 
1. Remember, for every scientific
hypothesis there exists an experiment such that a
"negative" result disproves it. If you don't find what
you're looking fora "negative" resultyou'd say with
confidence the hypothesis is wrong. "There exists
Extraterrestrial humanoid life in the Universe" is not
a scientific hypothesis. If you don't find
Extraterrestrials, it doesn't mean they don't existyour
range of investigation could never be sufficiently large.
But as ridiculous as it sounds, " The Moon is made of
cheese" is a scientific claim assuming there
exists means to examine the Moon in sufficient detail. No
such test exists for Extraterrestrials. 
THOUGHT PROBLEM: WHAT IS THE TANGENT FOR FOLLOWING RUN AND
RISE VALUES? Compute rise/run, rise = 120 m, run = 1 kilometer. 
4. added mass = (rise/run)*time. Think about why the mass
increases. 
7. For 3.14159...., , the number of radians in a
halfcircle, what are the two lengths? Think about #2
and other dimensionless ratios. 
CH 1  EXS/PROBS: 10; 11; 15; 13; 56; 26; 27. NOTE: FOR #10,
SEE SEC 1.4 EXAMPLES. 
11.mass = density* sphere volume w/ required
conversions. 
15. Find x1 = number of seconds in 365.24 d with 5 sig. figs. Compute x1  x2*100%/x1, where x2 = pi*10^{7}
and pi = 3.14159..... and % is short hand for
division. Use sig. fig. rules for
subtraction/addition, multiplication and division. Visit: http://library.thinkquest.org/10796/ch1/ch1.htm
. 
13;;;; 890 km = 890,000 m with 2 sig. figs, precise to the
10,000's place (in m) or 10's place (in km), a large number
with low precision. Now 10 m is precise to the 10's place.
You'd write 890 km = 890,000 m and 10
m = 0.01 km. Thus, 890 km + 0.01
km = 890.01 km = 890 km. For the given precisions, adding
10 m has no effect after rounding. PE = x1 
x2/x1*100%, where x1 = 890.01 km and x2 = 890 km
and % is short hand for division. The difference is zero after rounding. See http://library.thinkquest.org/10796/ch1/ch1.htm
. 
52;;;. Period = 1/frequency; # cycles = frequency*time.

26;;;. Done in class lecture notes in some
form.. 
27;;;. See section 1.8. There are three displacements. With respect
to page, the first is vertical, the second horizontal
and the third lies 45 degrees above horizontal with magnitude 3.1
km. Find D_{x} and D_{x}, x and y
components of total displacement vectorD.
Clearly D_{x} = 4.0 + the xcomponent of third
displacement and D_{y} = 2.6 + ycomponent of third
displacement. Find vectorD magnitude using the
Pythagorean Th. Tan theta = Dx/Dy where theta is related
angle. In what quadrant does vector D point? 