In this experiment, you measure  the parameters --mass m  and  spring constant k --- of an oscillating system and check whether the  period  T is as theory predicts. Consider  the mechanical oscillator illustrated in figures  13-2 and 13-13 of the textbook (Young and Freedman) .  At equilibrium, the mass  has zero force on it; there   the spring is neither stretched or compressed. When x is negative, the spring is compressed. Otherwise it is stretched.  Fx = -kx is the x-component force causing the mass to return to the origin (x = 0) at all times;  when the mass moves away from the origin, it slows down and when it moves toward the origin it speeds up. 

This explains all kinds of oscillators, whether they  be molecules vibrating back and force in the warm pen you are using to  write your lecture notes,   air molecules oscillating back and force as my voice travels across the lecture room,   or  an  “up and down” moving  piece of  string    supporting  a transverse standing wave such as on a guitar string. Such oscillations are everywhere, including   your quartz watch. 

 
In  Chapter 13,   Newton’s second Law is applied to a mass m attached to a spring. According to  Newton, the resultant force vector on an object of mass m at a given moment  is m times the acceleration.  In Chapter 13 and throughout the sequence, we explore this law  in   many examples in which the force  points towards x = 0. In this experiment you will test the theory for the special case of a vertically oscillating mass-spring system. The x component of force Fx = -kx leads to the result that

x= Acos(2πt/T) ,

where A is the amplitude and T is the period.  See section 13-2, especially figure 13.9 and equation 13-13.  On page 425 we discover :

T TH= 2π· (1)
 
Note that you may choose the positive x direction to be downward which means x is positive when the vertical spring is stretched.  To test the theory, you will measure the parameters (Mass m,  Spring Constant k )  that appear  in the theoretical expression for  T to obtain a theoretical value  TTh. ---see equation 1.  By a timing procedure, you will directly measure an experimental value TEX, and then compare  TTh  with TEX . (See attached data sheet. )  In particular,  you do the following for the mass-spring system:

(a) Measure the parameters m and k that appear in your expression for the period in  equation (1) and  use them to compute TTH.

(b) Measure the time t for a known number of cycles n (n = 10) and compute the experimental value of the period TEX = t/n.  You will measure Tex  5 times and compute the average TEX_BEST. From  this, you will also compute R/N (N= 5)  or standard deviation of the mean Sm like you did in the  Galileo lab this gives the statistical uncertainty in multiple measurements  when the random errors are larger than the instrument error in a single, “simple”  measurement.   The instrument   error is ΔT inst =  0.001 s /n  or  0.0001 s/n  ( where n = 10),  depending on the timer resolution.  The uncertainty  ΔTEX   you choose will either be   ΔT inst or R/N (or Sm) , which ever is larger.  See attached data sheet. In either case, the uncertainty is rounded to just one digit and we round the average (“best”) value to the same decimal place.

(c)  Compute the uncertainties in the values TEX and TTH, then test the proposition that TTH = TEX using the criteria we used in centripetal acceleration lab:

|TEX – TTH| < 2(ΔTEX + ΔTTH),

 
PROCEDURE

As in figure 13-17, you will hang a tapered spring vertically from a support with the small end of the spring at the top. This spring taper direction is important  for an accurate reading. The narrowing of the spring’s diameter toward the top allows the spring to stretch uniformly along its entire   length. The narrowing toward the top means the upper half of the spring is stiffer than the lower half. This stiffness “gradient”  is necessary because  the  upper part  supports the weight of the lower part and so must be stiffer if  it is to have the same  stretch per unit length as the lower.

(Q-1) You will add a mass of value m = 0.30 kg as suggested in figure 11-3 and allow the system to oscillate  up and down.  Remember, the hanger already has mass 50 g, so you will add 0.250 kg. The formula for the period is given by equation (1) but there is one complication that has to do with the correct value of the mass. While the system vibrates up and down, different parts of the spring move at different speeds. The effective mass ms,Eff  of the spring adds to the system’s inertia and  kinetic energy storage capacity. It  turns out that the mass m includes  both 0.30 kg and one- third of the mass of the spring; a calculus derivation shows that ms,Eff =  ms/3, where ms is the spring mass.  You may enter this expression under (Q-1) of the attached  data sheet.

(Q-2)    Beginning  with  equation (1), it is easy to derive  (using   Math 1 and 3 methods)
the expression for the uncertainty in the theoretical  value TTH of the period :


The expression contains the “best “ values from discussions below.  
  Δm and Δk  are the uncertainties in the oscillating mass m and spring constant k discussed below.
 

(Q-3)  To find the value of the spring constant k, use a sliding caliper jaw to record the position x’ of the bottom of the weight hanger with weights of mass M = 100, 200, 300 , 400 and 500 grams (g) suspended from the spring.  Plot values of force in newtons  vs  x’ in meters and find the spring constant k in N/m with uncertainty Δk. 
Note: The uncertainties in x’   and the hanging masses M should be very small . Thus, the  precision of your value of k will nearly  be limited by the graphing process. Thus, you can proceed without using error bars which will be discussed in a future lab. The least squares fit computational method for determining the slope will also be addressed later.  To get k, we will use LOGGER PRO’S REGRESSION CURVE FIT and the RSME, an error in the slope.

(Q-4) Weigh the spring to find ms  and compute the effective mass ms,Eff.  Enter the value mo = 0.30 kg.

Compute the total mass m = ms,Eff  + mo. Use this value along with kbest   to find T TH = 2π·
Compute the uncertainty ΔTTH assuming an uncertainty of  1 g for you mass measurements or use values given in  class discussion using least counts. .  See (Q-2) and (Q-3).

(Q-5) Suspend  0.30 kg from the spring, displace it slightly and determine the experimental period TEX.

Make at least 5 trials and count at least 10 cycles for each trial:
You will measure TEX  5 times and compute the average TEX-BEST. From  this, you will also compute R/N, where N = 5;  this gives the statistical uncertainty of multiple measurements  when the random errors are larger than the instrument error in a single, “simple”  measurement.   The instrument   error is ΔT inst =  0.001 s /n or 0.0001 s/n  ( where n = 10),  depending on the timer resolution.  The uncertainty  ΔTEX   you choose will either be   ΔT inst or R/N (or Sm) , which ever is larger.  In either case, the uncertainty is rounded to just one digit and we round the average (“best”) value to the same decimal place.

(Q-6)  Compare the discrepancy between the theoretical and experimental values to the sum of their uncertainties.