| ANSWERS QUIZ 20 |
| Problems 4, 6, 12, 14, 16, 28, 40, 42, 44, 46 |
| 4. 2.3x10 -4 (N) |
| 6. 20 degrees |
| 12. ( a) downward (b) into the paper (c) right |
| 14. 1.6 m |
| 16. While electric field is on: v = 2.5x10 6 m/s . After the electric field is turned off: r = 4.1 x10 -3 m. |
| 28. In all cases your right thumb points out in the direction of the current and your right fingers curve counter clockwise. See Table 20-1, point 1., the magnetic field due to a long wire. |
| 40. I = 19.4 (A) into the page for the diagrams I drew on the board for this problem. In the those diagrams the magnetic field from the wire was vertically down, which is the correct direction from the right hand rule , Table 20-1 , point 1. |
| 42. (a) 6700 (A) , right. (b) unstable (c) 6700 (A), left. |
| 44. Assume the two parallel
currents flow out of the page. You can have the wires horizontally
displaced from one another. Let wire B be positioned to
the right of wire A, i.e. wire A is on the left and wire
B is on the right. When you hand in this problem, please
show a diagram reflecting this set up. Assume the
currents are out. (a) 2.7x10 -6 T, up (b) 5.3x10 -6 T, down. (c) not equal and opposite (d) 1.1x10 - 5 N/m. |
| 46. magnitude Bnet = 1.75x10 -4 T. The net field points 14 degrees below the positive x-axis, in the fourth quadrant. |