| Quiz 16 Chapter 16 problems: 12, 13, 14, 15, 23, 24, 25, 26, 27, 28, 37, 38 , 41, 42 |
| TURN IN: 12, 14, 24, 26, 28, 38 [A only; B is extra Credit (EC)], 42 (EC) |
| Hints provided soon ! |
| 12. This should be an easy problem. Please
email with comments on this exercise. What gave you
trouble?
Here are some suggestions: Label the charges, staring from the
left, as 1, 2 and 3. |
|
14. Please email with comments on this exercise. What
gave you trouble? Note: a = 0.100 m and 6x10-3 C = q1
= q2 = q3 = q4
. |
| 24. A proton is positive, so the force points in the same direction as the electric field vector. Note: E = F/Q. Look up the proton charge using Google or the textbook |
| 26. Use equation 16-4a or 16-4b. You should be able to find the field direction given that the lines leave positive charges. |
| 28. See the hints for the computation of the net
electric force on charge 3, problem 12. See also example
16-8. Net electric field has magnitude : F1NET = k|q1|/(0.040)2 + k|q2|/(0.040)2 , where -8x10-6 C = q1 and 7x10-6 C = q2 . We assume that q2 is on the right end and q1 is on the left end of the horizontal segment between the two charges. Note the sum above is positive, but the force points left. |
| More hints later. |