ANSWERS
Quiz 13; Problems 3, 4, 9, 10, 11, 12, 29, 30, 38, 39, 46, 47, 50, 51, 52
TURN IN: 4, 10, 12, 30, 38, 46,
4. Use TC = (5/9)(TF - 32)  or TF = 9/5TC + 32 . Either way will get your answer in F. 
10. Use equation 13-1b.  The steel rivet must be cooled down in order to fit in the  hole.  That way,  when the temperature rises again, there will be a very tight fit--- so tight that the structure will survive everyday wear and tear, not to mention possible earth shaking. Thus equation 13-1b is with a negative change in temperature. Set up the following equation:
 1.869 = 1.871 + (1.871)·(alpha)·(change in temperature). Solve for the negative change in  temperature.  Then find the NEW temperature, given  the initial temperature of 20 oC.  

12. Equation 13-2. In the spirit of the previous problem, I want you to find the  NEW volume after you find the CHANGE in volume using the initial given volume. To get the initial volume, use a general formula,  which you can Google or look up in a book. (See example 13-11 for example)

29. See example 13-13 and the equation directly above it on page 366:
 P1V1/T1 = P2V2/T2 .  Solve for the new volume V2 .  The first volume is given. Note P1 = 1.00 atm and T1 =  273 K (under STP conditions explained on page 364),  whereas P2 = 3.00 atm. Note: You must convert  T2 = 38.0 oC to Kelvin .
30. See the previous problem, example 13-13 and the equation directly above it on page 366 for helpful methodology. 
 P1V1/T1 = P2V2/T2 . IN THIS CASE, YOU WANT T2. Convert temperatures to K. V2 = (1/9) V1 .  The first temperature is given. The first pressure = 1.0 atm,  the second pressure = 40.0 atm .
38. See the previous problem, example 13-13 and the equation directly above it on page 366 for helpful methodology. 
 But P1V1/T1  is NOT  P2V2/T2 . Why? Because the numbers of moles is not constant. You have to use the ideal  gas law which states that PV = nRT in a different way.  We see that n = PV/(RT) = number of moles. Now write n1 = P1V1/RT1   
and n2 = P2V2/RT2  . Subtract them to find  the difference between the number of moles in the two cases:  n1 - n2 = P1V1/RT1   -  P2V2/RT2  . Then divide the difference by n1 to get the fractional change.  Note that this difference is positive since you initially had more moles.   Note that  P1 =  P2 .       Convert temperatures to Kelvin K .
46. (a) (3/2)kT is the average kinetic energy. See equation  13-8. (b) N(3/2)kT = n(3/2)RT, where n is the number of moles. Note that N is the number of particles; I did a conversion relating R to k.